96=12x^2+4x

Solution for 96=12x^2+4x equation:

96=12x^2+4x

We move all terms to the left:

96-(12x^2+4x)=0

We get rid of parentheses

-12x^2-4x+96=0

a = -12; b = -4; c = +96;
Δ = b2-4ac
Δ = -42-4·(-12)·96
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-68}{2*-12}=\frac{-64}{-24}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+68}{2*-12}=\frac{72}{-24}
=-3
$